کد ++cمربوط به : digit 2 text (تبدیل عدد به نوشته)

[زکریا فتاحی]

#include <iostream.h>
#include <conio.h>

int enter();
int numbers(long int);
void convert(int);
void process(int);
const d=5;
int digit[d],count;
char str1[10][10]={" ","Yek","Do","Se","Chahar","Panj","Shesh","Haft","Hasht","Noh"};
char str2[10][10]={"Dah","Yazdah","Davazdah","Sizdah","Chahardah","Panezdah","Shanezdah","Hefdah","Hejdah","Noozdah"};
char str3[10][10]={" ","Dah","Bist","Si","Chehel","Panjah","Shast","Haftad","Hashtad","Navad"};
char str4[10][10]={" ","Sad","Devist","Sisad","Chaharsad","Pansad","Sheshsad","Haftsad","Hashtsad","Nohsad"};
char str5[d][10]={"","Hezar","Milion","Milliard","Trilliard"};
int first[100];
int check(int i);
void main()
{
    clrscr();
    int num;
   cout<<"   Convert Digits to Text (Farsi Version) \n\n";
    cout<< "enter number with less than "<< (d*3) <<" digits: ";
   num=enter();
    process(num);

   cout << "\n\n  there is "<<num <<" digits entered \n\n - - - - - - - - - - - - - - - - - - -\n \n";

   cout << (num>d*3?"~... too big number !!":"");
    if(num<=d*3)
        for (int i=count-1;i>=0;i--)
       {
         if(digit[i]>0)
         {
                convert(digit[i]);
              cout <<str5[i];
            cout <<(check(i)?"o ,":" ,");
         }
       }

    getch();
}
void convert(int n)
{
     int a;
   a=n/100;
   if(a>0)
        cout<< str4[a] << (n%100>0?"o ":"");
   n%=100;
   if (n>=20)
          cout<< str3[n/10] << (n%10>0?"o ":" ") << str1[n%10] << ' ';
   else if (n<20 && n>=10)
          cout<< str2[n%10] << ' ' ;
   else if (n<10)
            cout << str1[n] << ' ';
}
int enter()
{
  int i;
  i=getch();
  int num=0;

  while (i!=13)
      {
        if (i > 47 && i<58 || i==8)
      {
            if (i==8  && num>0)
         {
                num--;
             first[num]=0;
             putch(i);
             putch(' ');
         }
         else
         {
              first[num]=i-'0';
            num++;
         }
         putch(i);
        }
      i=getch();
   }
   return (num);
}
void process(int num)
{
    int k=1,m=0,i;

    for(i=num-1;i>=0;i--)
   {
       m=first[i]*k+m;
      k*=10;
       if (k>100)
       {
            digit[count]=m;
            m=0;k=1;;
             count++;
      }
   }
   if(m>0)
        {
      digit[count]=m;
      count++;
      }
}
int check(int i)
{
int k=0;
    for (int j=i-1;j>=0;j--)
       if (digit[j]>0)
          k=1;
return k;
}

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